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MarsNIIT
25-11-2007, 10:56 AM
Thấy anh em mê Toán quá mà forum lại chưa tích hợp cách viết công thức Toán, nay cài cái code để anh em tiện lại hơn trong việc đánh công thức :


1.Các chỉ số trên và dưới :http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20a%5En%20,%20a_n%20,%20C_n%5 Ek,%20log_2%28x+3%29
\large a^n , a_n , C_n^k, log_2(x+3)2. Phân số :http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cfrac%7Bx%5E2+5x%20+4%7D%7B% 5Cfrac%7B3%7D%7Bx%7D+1%7D
\large\frac{x^2+5x +4}{\frac{3}{x}+1}

3.Căn thức : http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Csqrt%7B2+n%7D%20,%20%5Csqrt %5B3%5D%7B4+q%7D%20,%20%5Csqrt%5Bk%5D%7B7+13%7D
\large\sqrt{2+n} , \sqrt[3]{4+q} , \sqrt[k]{7+13}4.Tổng và tích : http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20%5Csum%20a%20,%20%20%5Csum% 5Climits_%7Bi=1%7D%5E%7Bn%7D%20a_i,%20%5Cpro_%7Bi= 1%7D%5Ekb_1
\large \sum a , \sum\limits_{i=1}^{n} a_i, \pro_{i=1}^kb_15.Hệ : http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cleft%5C%7B%20%20%5Cbegin%7B array%7D%7Bl%7D%20%20%20%20x+%5Csqrt%7By%7D%20=%20 1%20%5C%5C%20%20%20%20x%20-%20y%5Ex%20=3%20%20%20%5Cend%7Barray%7D%20%20%5Cri ght.
\large\left\{ \begin{array}{l} x+\sqrt{y} = 1 \\ x - y^x =3 \end{array} \right.6.Giới hạn: http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20%5Clim_%7Bx%5Cto%200%7D%20f %28x%29
\large \lim_{x\to 0} f(x)7.Tích phân : http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cint%5Climits_%7Ba%7D%5E%7Bb %7Df%28x%29dx
\large\int\limits_{a}^{b}f(x)dx8.Góc : http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20%5Chat%7BA%7D%20=60%5Eo,%20 %5Cwidehat%7BABC%7D+%5Cwidehat%7BBCA%7D+%5Cwidehat %7BCAB%7D%20=%202%5Cpi

\large \hat{A} =60^o, \widehat{ABC}+\widehat{BCA}+\widehat{CAB} = 2\pi9.Các quan hệ giữa phần tử : http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20a%20=%20b%20,%20a%20%5Cneq% 20b,%20a%20%3E%20b,%20a%20%3C%20b,%20a%20%5Cgeq%20 b,%20a%20%5Cleq%20b,%20a%20%5Csem%20b,%20a%20%5Ceq uiv%20b

\large a = b , a \neq b, a > b, a < b, a \geq b, a \leq b, a \sem b, a \equiv b10.Quan hệ tập hợp :http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20A%20%5Ccap%20B%20,%20A%20%2 0%5Ccup%20C%20,%20A%20%5Cin%20S%20,%20A%20%20%5Cno tin%20Z%20,%20A%20%20%5Csubset%20T,%20A%20%20%5Csu pset%20N

\large A \cap B , A \cup C , A \in S , A \notin Z , A \subset T, A \supset N11. Tổ hợp :http://njet.oops.jp/cgi/mimetex.cgi?%5CLarge%7Bn%5Cchoose%20k%7D

\Large{n\choose k}12. Gõ dấu các và xuống dòng trong công thức
i,Xuống dòng: http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20a%20+%20x=%20b%20%5C%5C%20b +x=a

\large a + x= b \\ b+x=aii,Dấu cách : http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20a%20%5C%20%5C%20b%20%5C%20% 5C%20%5C%20%5C%20%5C%20%5C%20%5C%20c

\large a \ \ b \ \ \ \ \ \ \ c13. Gõ gạch đầu và gạch chân:http://njet.oops.jp/cgi/mimetex.cgi?%20%5Coverline%7Bab%7D%20;%20%5Cunderl ine%7Bab%7D

\overline{ab}; underline{CD}Chú ý: Không thể chèn được nhiều chữ liền nhau trong công thức toán học ( khi hiển thị sẽ bị lối ).
Nếu muốn gõ kèm chữ trong công thức bạn có thể gõ như sau :

\text{Xet ham so }\ \ \ f(x) = \sqrt{3+x^2} + log_3x + sin(\pi +x)Sẽ được
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ctext%7BXet%20ham%20so%7D%5C %20%5C%20%5C%20%20f%28x%29%20=%20%5Csqrt%7B3+x%5E2 %7D%20+%20log_3x%20+%20sin%28%5Cpi%20+x%29

14, Dấu giá trị tuyệt đối , tập hợp :http://njet.oops.jp/cgi/mimetex.cgi?%20%5C%7Ca%5C%7C%20,%20%5C%7Ba_1,...,a _n%5C%7D

\|a\| , \{a_1,...,a_n\}15, Tích : http://njet.oops.jp/cgi/mimetex.cgi?%20%5Cbigpro_%7Bi=1%7D%5En%20a_i%20,%2 0%5Cbigpro_%7Bi%20%5Cneq%20j%7D%5En%20a_ia_j

\bigpro_{i=1}^n a_i , \bigpro_{i \neq j}^n a_ia_j 17.Dấu tương đương : http://njet.oops.jp/cgi/mimetex.cgi?%5CLeftrightarrow%20,%20%5Clarge%20%5C Leftrightarrow

\Leftrightarrow , \large \Leftrightarrow 18,Tồn tại : http://njet.oops.jp/cgi/mimetex.cgi?%5Cexists%20,%20%5Clarge%20%5Cexists

\exists , \large \exists19. Dấu ngoặc dưới http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cunderbrace%7B%20a+b+%5Ccdot s+z%20%7D_%7B26%7D

\large\underbrace{ a+b+\cdots+z }_{26}20. Dấu vuông góc http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cperp

\large\perp21. Hiển thị màu http://njet.oops.jp/cgi/mimetex.cgi?%5Cred%5CLarge%5C%20e%5Ex=%5Csum_%7Bn= 0%7D%5E%5Cinfty%5Cfrac%7Bx%5En%7D%7Bn%21%7D

\red\Large\ e^x=\sum_{n=0}^\infty\frac{x^n}{n!}22. Các kiểu chữ cái

http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cmathrm%7BABCxyz%7D

\large\mathrm{ABCxyz}
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cmathit%7BABCxyz%7D


\large\mathit{ABCxyz}http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cmathcal%7BABCxyz%7D

\large\mathcal{ABC}
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cmathbb%7BABCNZR%7D

\large\mathbb{ABCNZR}http://njet.oops.jp/cgi/mimetex.cgi?%5CLarge%5Cmathscr%7BABC%7D

\large\mathscr{ABC}23. Ma trận http://njet.oops.jp/cgi/mimetex.cgi?%5CLarge%5Cmathbf%7BX%7D%20=%5Cleft%28 %20%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B11%7D%20&%20x_%7B12%7D%20&%20%5Cldots%20%5C%5Cx_%7B21%7D%20&%20x_%7B22%7D%20&%20%5Cldots%20%5C%5C%5Cvdots%20&%20%5Cvdots%20&%20%5Cddots%5Cend%7Barray%7D%20%5Cright%29

\Large\mathbf{X} =\left( \begin{array}{ccc}x_{11} & x_{12} & \ldots \\x_{21} & x_{22} & \ldots \\\vdots & \vdots & \ddots\end{array} \right)23. Kí hiệu đồng dư:

http://njet.oops.jp/cgi/mimetex.cgi?a%20%20%5Cequiv%20b%20%5Cquad%20%28mod %20%5C,%20b%29

a \equiv b \quad (mod \, b)24. Các kích cỡ của công thức

http://njet.oops.jp/cgi/mimetex.cgi?%5Ctiny%5Csqrt%7Ba%5E2+b%5E2%7D

\tiny\sqrt{a^2+b^2}http://njet.oops.jp/cgi/mimetex.cgi?%5Csmall%5Csqrt%7Ba%5E2+b%5E2%7D

\small\sqrt{a^2+b^2}
http://njet.oops.jp/cgi/mimetex.cgi?%5Cnormalsize%5Csqrt%7Ba%5E2+b%5E2%7D

\normalsize\sqrt{a^2+b^2}
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Csqrt%7Ba%5E2+b%5E2%7D

\large\sqrt{a^2+b^2}http://njet.oops.jp/cgi/mimetex.cgi?%5CLarge%5Csqrt%7Ba%5E2+b%5E2%7D

\Large\sqrt{a^2+b^2} http://njet.oops.jp/cgi/mimetex.cgi?%5CLARGE%5Csqrt%7Ba%5E2+b%5E2%7D


\LARGE\sqrt{a^2+b^2}
http://njet.oops.jp/cgi/mimetex.cgi?%5Chuge%5Csqrt%7Ba%5E2+b%5E2%7D

\huge\sqrt{a^2+b^2}http://njet.oops.jp/cgi/mimetex.cgi?%5CHuge%5Csqrt%7Ba%5E2+b%5E2%7D

\Huge\sqrt{a^2+b^2}Đóng khung http://njet.oops.jp/cgi/mimetex.cgi?%5Cfbox%7Beuler%7D

\fbox{euler}Chữ dưới: http://njet.oops.jp/cgi/mimetex.cgi?%5CLarge%5Clongrightarrow_%7B%5Ctext%7 Beuler%7D%7D

\Large\longrightarrow_{\text{euler}} Chữ trên: http://njet.oops.jp/cgi/mimetex.cgi?%5CLarge%5Clongrightarrow%5E%7B%5Ctext %7Beuler%7D%7D

\Large\longrightarrow_{\text{euler}}Cách gõ các chữ cái Hy Lạp viết thường :

http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Calpha http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbeta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cgamma http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cdelta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cepsilon http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cvarepsilon http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Czeta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ceta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ctheta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cvartheta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ciota http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ckappa http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Clambda http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cmu http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cnu http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cxi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20o http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Coi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cpi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cvarpi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Crho http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cvarrho http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Csigma http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cvarsigma http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ctau http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cupsilon http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cphi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cvarphi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cchi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cpsi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Comega

\large\alpha
\large\beta
\large\gamma
\large\delta
\large\epsilon
\large\varepsilon
\large\zeta
\large\eta
\large\theta
\large\vartheta
\large\iota
\large\kappa
\large\lambda
\large\mu
\large\nu
\large\xi
\large o
\large\oi
\large\pi
\large\varpi
\large\rho
\large\varrho
\large\sigma
\large\varsigma
\large\tau
\large\upsilon
\large\phi
\large\varphi
\large\chi
\large\psi
\large\omegaCách gõ các chữ cái Hy Lạp viết hoa :

http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CGamma http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CDelta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CTheta http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CLambda http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CXi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CPi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CSigma http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CUpsilon http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CPhi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CPsi http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5COmega.

\large\Gamma
\large\Delta
\large\Theta
\large\Lambda
\large\Xi
\large\Pi
\large\Sigma
\large\Upsilon
\large\Phi
\large\Psi
\large\OmegaLưu ý: \large chỉ là lệnh làm cho chữ to ra thôi, chứ nó không đóng vai trò chính trong bảng trên.

Các toán tử lớn:
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Csum
\large\sum
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cprod
\large\prodhttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ccoprod
\large\coprod
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cint
\large\int
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigcup
\large\bigcuphttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigcap
\large\bigcaphttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigsqcup
\large\bigsqcuphttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Coint
\large\ointhttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigvee
\large\bigvee
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigwedge
\large\bigwedgehttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigoplus
\large\bigoplushttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigotimes
\large\bigotimeshttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbigodot
\large\bigodothttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbiguplus
\large\biguplus

http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ctop
\large\tophttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cbot
\large\bot
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cpartial
\large\partial
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cnabla
\large\nabla
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cddots
\large\ddotshttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cvdots
\large\vdots
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Ccdots
\large\cdotshttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cflat
\large\flat
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cclubsuit
\large\clubsuithttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cspadesuit
\large\spadesuithttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CRe
\large\Rehttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CIm
\large\Imhttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cdag
\large\ddaghttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5CS
\large\S
http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%20%5CP
\large \Phttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5C%
\large\%
http://njet.oops.jp/cgi/mimetex.cgi?%5Cred%5Cnormalsize%5Ccalendar
\red\normalsize\calendar
http://njet.oops.jp/cgi/mimetex.cgi?%5Cnormalsize%5Cred%5Ctoday
\normalsize\red\todayĐịnh thức:

http://njet.oops.jp/cgi/mimetex.cgi?%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7Da&b%5C%5Cc&d%5Cend%7Barray%7D%5Cright%7C
\left|\begin{array}{cc}a&b\\c&d\end{array}\right|
a,b trên 1 hàng thì phải cho thêm dấu &, còn c,d ở hàng duới thì cho thêm dấu \\ , nhìn kĩ sẽ rõ
Ex:

http://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Cleft%7C%5Cbegin%7Barray%7D% 7Bcc%7Df%27%28x%29&f%27%28y%29%5C%5C%20g%27%28x%29&g%27%28y%29%5Cend%7Barray%7D%5Cright%7C
\large\left|\begin{array}{cc}f'(x)&f'(y)\\ g'(x)&g'(y)\end{array}\right|http://njet.oops.jp/cgi/mimetex.cgi?%5Cleft%7C%20%5Cbegin%7Bmatrix%7D%20a_ 1%20&%20a_2%20%5C%5Ca_3%20&%20a_4%20%5Cend%7Bmatrix%7D%20%5Cright%7C
\left| \begin{matrix} a_1 & a_2 \\a_3 & a_4 \end{matrix} \right|Dấu ko chia hết là http://njet.oops.jp/cgi/mimetex.cgi?%5Cnot%5Cvdots
\not\vdotshttp://njet.oops.jp/cgi/mimetex.cgi?%5Ccos%5Cfrac%7BA%7D%7B2%7D%20,%20%5Cc os%5Cfrac%7BB%7D%7B2%7D,%5Ccos%5Cfrac%7BC%7D%7B2%7 D
\cos\frac{A}{2}, \cos \frac{B}{2},\cos \frac{C}{2}
http://njet.oops.jp/cgi/mimetex.cgi?f%5E%7B%282%29%7D%20%28x%29 hay http://njet.oops.jp/cgi/mimetex.cgi?f%5E%7B%27%27%7D%28x%29
f^{(2)} (x) or f^{''}(x)http://njet.oops.jp/cgi/mimetex.cgi?%5Cstackrel%7B%5Cfrown%7D%7BAB
\stackrel{\frown}{ABhttp://njet.oops.jp/cgi/mimetex.cgi?%5Chuge%5Cfrown
http://njet.oops.jp/cgi/mimetex.cgi?AB
\huge\frownhttp://njet.oops.jp/cgi/mimetex.cgi?%5Clarge%5Csqrt%5Bn%5D%7Ba%7D

\large\sqrt[n]{a}http://njet.oops.jp/cgi/mimetex.cgi?%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bc%7 Da=b%5C%5C%20b=c%5Cend%7Barray%7D%5Cright.
http://njet.oops.jp/cgi/mimetex.cgi?%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Da= b%5C%5C%20b=c%5Cend%7Barray%7D%5Cright.
\left\{\begin{array}{c}a=b\\ b=c\end{array}\right
\left[\begin{array}{c}a=b\\ b=c\end{array}\right\left {\begin \\a=b \\a=c
\left [\begin \\a=b \\a=chttp://njet.oops.jp/cgi/mimetex.cgi?%5Cleft%7B%20%5Cleft%5B%20a%20%5C%5C%2 0b%20%5Cright.%20%20%5C%5C%20%5Cleft%5B%20c%20%5C% 5Cd%20%5Cright.%20%5Cright.
\left{ \left[ a \\ b \right. \\ \left[ c \\d \right. \righthttp://njet.oops.jp/cgi/mimetex.cgi?%5C%5Bsqrt%7Bx%7D%5D
\[sqrt{x}]

LeGiang
25-11-2007, 11:06 AM
viet bai chua duoc

myhanh
25-11-2007, 12:13 PM
Em sử dụng cái này phải không?
http://www.forkosh.com/mimetex.html

MarsNIIT
25-11-2007, 12:34 PM
đúng rồi anh myhanh, lẽ ra em sẽ cài tập tin .cgi nhưng dính đến host lắm nên em mượn host của nó luôn và bảo đảm không die vi nó chuyên về cái vụ này mà, bây giờ cách thức gõ công thức ra sao mới quan trọng, chỉ cần tra ra là biết nhưng em ...rối quá , hihi

anh myhanh giúp em nhé:
gõ code xong chỉ cần bôi đen code đó và click hình http://www.sims2wiki.info/images/2/24/Icon-math.gif trên thanh công cụ .

myhanh
25-11-2007, 04:02 PM
Chỉ test thôi nha!
Để anh thử lại câu 2 đề thi xem sao:
Giải phương trình:
|ln(x^2-x+1)|+|ln(2x^2-x+1)|=|ln[(x^2-x+1)(2x^2-x+1)]|
Câu 4:
Cho x, y là hai số thực thoả mãn:
\left\{ \text{0\leq x\leq y\leq 6\\x+y\leq 10} \right
Chứng minh rằng:
x^2+y^2\leq 52
Bây giờ xinh ra phết chứ lị!